9 votes 9 votes A pipeline $P$ operating at $400$ MHz has a speedup factor of $6$ and operating at $70$% efficiency. How many stages are there in the pipeline? $5$ $6$ $8$ $9$ CO and Architecture isro2013 co-and-architecture pipelining + – makhdoom ghaya asked Apr 26, 2016 retagged Nov 13, 2017 by Arjun makhdoom ghaya 8.5k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes S=Efficieny(n)*M(Stages) M=S/n M=ceil(60/7)=~9 Paras Nath answered Sep 10, 2016 Paras Nath comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes Speedup = m * efficiency. 6 = 0.7m m = 8.57 If we take 8 stages, efficiency becomes 75%. If we take 9 stages, efficiency becomes 66%. Less-than-mentioned efficiency sounds more practical than more-than-mentioned; so 9 Option D. JashanArora answered Dec 1, 2019 JashanArora comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes Given Data, Speedup factor=6. efficiency=70% =0.7 Step-1: Here, we have to find out number of stages. Efficiency = Speedup factor/ Number of stages 0.7 = 6 / Number of stages Step-2: Number of stages = 8.56 = 9 topper98 answered Mar 23, 2020 topper98 comment Share Follow See all 0 reply Please log in or register to add a comment.