0 votes 0 votes From a pack of 52 cards , 4 cards are drawn . Find the probability that they are the 4 honours of same suit ? Probability probability + – Dexter asked Apr 26, 2016 Dexter 600 views answer comment Share Follow See 1 comment See all 1 1 comment reply Dexter commented Apr 26, 2016 reply Follow Share is it 4*13C4/ 52C4 ? 0 votes 0 votes Please log in or register to add a comment.
–1 votes –1 votes Honours : King, Queen, Jack & 1. P = 4/52 * 3/51 * 2/50 * 1/49 = 24/6497400 = 0.000003693 Digvijay Pandey answered Apr 26, 2016 Digvijay Pandey comment Share Follow See all 4 Comments See all 4 4 Comments reply Arjun commented Apr 26, 2016 reply Follow Share 4,3,2,1 corresponds to? 0 votes 0 votes Dexter commented Apr 26, 2016 reply Follow Share No i dodnt think its right . Honour cards are ace king queen and jack each suit have 1 each --- implies each suit has all this 4 cards ( 1j 1k 1q and one ace ) and each suit has 13 cards So i think it should 13C4/52C4( diamond) +13C4/52C4 (heart )+13C4/52C4 (clubs )+13C4/52C4 (spade)=4*13C4/52C4 0 votes 0 votes Arjun commented Apr 26, 2016 reply Follow Share @Dexter Why 13C4? What does that signify? The 4 cards are fixed in each set rt? 0 votes 0 votes Dexter commented Apr 26, 2016 reply Follow Share Sir it should be 4/ 52C4 . Those cards are fixed in each suit! 1 votes 1 votes Please log in or register to add a comment.