What is the maximum number of characters (7 bits + parity) that can be transmitted in a second on a $19.2$ Kbps line. This asynchronous transmission requires $1$ start bit and $1$ stop bit.
A Kilobit per second is a unit used to measure data transfer rates and is based on "Decimal multiples of bits". The symbol for Kilobit per second is Kbps or kb/s or kbit/s. There are 8 Kilobits per second in a Kilobyte per second.
Kilobyte (KB or K) = 1024 bytes (2 ^ 10) "binary kilobyte"
kilobyte (kB) = 1000 bytes (10 ^ 3) "decimal kilobyte"
Kilobit (Kb) = 1024 bits (2 ^ 10) "binary kilobit"
kilobit (kb) = 1000 bits (10 ^ 3) "decimal kilobit"
KBps = Kilobytes (1024 bytes) per second (binary)
kBps = kilobytes (1000 bytes) per second (decimal)
Kbps = Kilobits (1024 bits) per second (binary)
kbps = kilobits (1000 bits) per second (decimal)
bps = bits per second
in simple words ,
K- Binary system
k- Decimal system
So according to you K (capital) =1024 and k (small) =1000 for kilo.
Then in above question, bandwidth is given as 19.2Kbps then it should be equivalent to 19.2 * 1024 bps but in above solution value of 'K' is 1000. This is what contradicting.
Please confirm (means still need help) which is correct.