The Gateway to Computer Science Excellence
0 votes
A byte-addressable memory organized in 32-bit words according to big-endian. A program reads ASCII characters and stores them in successive byte locations, starting at location 1000. Show the contents of memory words at locations 1000,1004 for name “ Johnson ” .

Each word has a unique address and we have 32-bit word. So why cant we take 8-bits for each letter and store 4 letters per word.Thus we need only 2 addresses..

Where am i gng wrong ?
in CO and Architecture by Active (1.1k points) | 203 views
it is addressed by byte not word. And we need only 2 words here.
Sir can u pls give me d complete solution here , its still not clear..

Please log in or register to answer this question.

Quick search syntax
tags tag:apple
author user:martin
title title:apple
content content:apple
exclude -tag:apple
force match +apple
views views:100
score score:10
answers answers:2
is accepted isaccepted:true
is closed isclosed:true
50,737 questions
57,314 answers
105,085 users