Please help me out here :-

Question

A byte-addressable memory organized in 32-bit words according to big-endian. A program reads ASCII characters and stores them in successive byte locations, starting at location 1000. Show the contents of memory words at locations 1000,1004 for name “ Johnson ” .

Each word has a unique address and we have 32-bit word. So why cant we take 8-bits for each letter and store 4 letters per word.Thus we need only 2 addresses..

Where am i gng wrong ?

Comments

it is addressed by byte not word. And we need only 2 words here.

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Sir can u pls give me d complete solution here , its still not clear..