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A byte-addressable memory organized in 32-bit words according to big-endian. A program reads ASCII characters and stores them in successive byte locations, starting at location 1000. Show the contents of memory words at locations 1000,1004 for name “ Johnson ” .
Each word has a unique address and we have 32-bit word. So why cant we take 8-bits for each letter and store 4 letters per word.Thus we need only 2 addresses..
Where am i gng wrong ?
asked
Apr 27, 2016
in
CO and Architecture
Kiran Karwa
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it is addressed by byte not word. And we need only 2 words here.
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Sir can u pls give me d complete solution here , its still not clear..
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