679 views
0 votes
0 votes
A byte-addressable memory organized in 32-bit words according to big-endian. A program reads ASCII characters and stores them in successive byte locations, starting at location 1000. Show the contents of memory words at locations 1000,1004 for name “ Johnson ” .

Each word has a unique address and we have 32-bit word. So why cant we take 8-bits for each letter and store 4 letters per word.Thus we need only 2 addresses..

Where am i gng wrong ?

Please log in or register to answer this question.

Related questions

0 votes
0 votes
0 answers
2
Phantom5 asked Aug 21, 2018
242 views
Quoted:What data rate is needed to transmit an uncompressed 4" x 6" photograph every second with a resolution of 1200 dots per inch and 24 bits per dot (pixel)?1. 691,200...
0 votes
0 votes
1 answer
3
Phantom5 asked Aug 27, 2018
600 views
Quoted Question:One of the large unlicensed bands used for 802.11b WiFi is 2.4GHz. What is the length of these waves? Answer in feet.