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Answer given as option a )

My knowledge .
Rank of a matrix Q is 4 implies 1 out of 5 rows of Q is zero

linearly independent solution = n-r
n--> no of unknowns

r---> rank
therefore linerly independent solution = 5-4 = 1

What is linerly independent Rows ... ?

linerly independent vectors ?

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Option A : Row rank = Column rank. 

Row rank is given to be 4 which implies column rank is also four. Therefore, 4 linearly independent rows as well 4 linearly independent columns.

Proof : http://ocw.mit.edu/courses/mathematics/18-701-algebra-i-fall-2010/study-materials/MIT18_701F10_rrk_crk.pdf

I suggest you to read this once to understand linear independence : https://en.wikipedia.org/wiki/Linear_independence

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It is told the matrix is 5⨉6 matrix with order 4

So, order 4 means it is 4⨉6 matrix

It has linearly independent 4 rows 6 columns

Here (A) and (B) false

Now Among C) and D)

In C) Q=5⨉6 Matrix Qt = 6⨉5

QQt will give 5⨉5 matrix

but 5 th row reduces and matrix will be 4⨉5

Again determinant will be 0 and matrix will be non invertable

D) is perfect to be invertable

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