8085 is an 8 bit micro processor
87= 1000 0111
79= 0111 1001
Addition of both number will result into
= 1 0000 0000
They want the contents of all status bits :
Result is 00
S (sign) this bit is set to 1 if msb is set to 1 , but here MSB is 0 so S = 0
Zero flag : It set to 1 if result is 0 . here we obtain result 00 so zero flag is set to 1
CY : IT IS set to 1 if there is a carry out from MSB . here 1 ( underlined ) is a carry from MSB . So CY is set to 1
Hence option d is an answer
