Question

The dual of SOP(1,3,5,6)? How to calculate it without representing in terms of minterms ?

Comments

https://gateoverflow.in/38315/duality

Answer 1

F(1,3,5,6)= A'B'C+A'BC+AB'C+ABC'

dual of F is (A'B'C+A'BC+AB'C+ABC') = (A'+B'+C)(A'+B+C)(A+B'+C)(A+B+C')

Comments

@srestha dual and complement are different thing.

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yes I made mistake, Now see

just check the answer

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@srestha Yes,Now your answer is right.

Answer 2

Given Function is f(x,y,z)=x'y'z+x'yz+xy'z+xyz

Now what is dual?

The dual of a boolean expression is obtained by interchanging boolean sums and products and interchanging 0's and 1's.

So dual of given function f(x,y,z)=(x'+y'+z)(x'+y+z)(x+y'+z)(x+y+z)