Let the domain be the collection of all proposition.
$P(x)=x \ is \ a \ tutology$
$Q(x)=x \ is \ a \ contradiction$
$Q(x)=x \ is \ a \ contingency$
$\sim x \ is \ the \ negation \ of \ proposition \ x.$
$(a)The \ negation \ of \ a \ contradiction \ is \ a\ tautology$
$It \ means \ " for \ all \ propositions \ x \ such \ that \ x \ is \ a \ contradiction, \\ the \ negation \ ¬x \ is \ a \ tautology".$
$\forall x(Q(x) \rightarrow P(\sim x))$
$(b)The \ disjunction \ of \ 2 \ contingencies \ can \ be\ tautology$
$It \ means \ " There \ are \ x \ and \ y \ such \ that \ x \ and \ y \ are \ contingencies \\ and\ x \vee y \ is \ a \ tautology".$
$\exists x \exists y((R(x) \wedge R(y))\rightarrow P(x \vee y)$