edited by
3,170 views
0 votes
0 votes

Consider a system with 2 level cache. The access times of L1-Cache, L2-Cache and Main Memory are 1ns, 10ns and 500ns. The hit rate of L1 and L2 caches are 0.8 and 0.9 respectively. What is the average access time ?

edited by

2 Answers

Best answer
3 votes
3 votes

 Tavg = 0.8 x [1] + 0.2 x [ 0.9 x (1+10) + 0.1 x (1+10+500) ] ns

             = 13 ns

selected by
0 votes
0 votes

t1 * h1 + (1- h1) h2 t2 + (1-h1) (1-h2) tm

Tavg=0.8*1+0.2*0.9*10+0.2*0.1*500

         =10.98ns

check here similar one

https://gateoverflow.in/3653/gate2004-it_12

edited by
Answer:

No related questions found