edited by
444 views
1 votes
1 votes

You have two normal, fair, dice, with faces labelled $1,2, \dots 6$. If you throw both dice, which of the following is true about the total value shown by the dice?

  1. The probability that the total is $6$ is less than the probability that the total is $9$.
  2. The probability that the total is $6$ is equal to the probability that the total is $9$.
  3. The probability that the total is $6$ is greater than the probability that the total is $9$.
  4. None of the above.
edited by

1 Answer

1 votes
1 votes

Possible combination to get 6 as sum = (2,4) (4,2) (3,3) (5,1) (1,5)

Possible combination to get 9 as sum = (4,5) (5,4) (6,3) (3,6)

The probability that the total is 6 =$\frac{5}{36}=0.138$

The probability that the total is 9 =$\frac{4}{36}=0.111$

Here, The probability that the total is 6  > The probability that the total is 9

0.138 >0.111

 

Hence,Option(C)The probability that the total is 6 is greater than the probability that the total is 9.

Related questions

4 votes
4 votes
1 answer
1