Possible combination to get 6 as sum = (2,4) (4,2) (3,3) (5,1) (1,5)
Possible combination to get 9 as sum = (4,5) (5,4) (6,3) (3,6)
The probability that the total is 6 =$\frac{5}{36}=0.138$
The probability that the total is 9 =$\frac{4}{36}=0.111$
Here, The probability that the total is 6 > The probability that the total is 9
0.138 >0.111
Hence,Option(C)The probability that the total is 6 is greater than the probability that the total is 9.