0 votes 0 votes Mathematical Logic set-theory + – Sourabh Kumar asked May 20, 2016 Sourabh Kumar 912 views answer comment Share Follow See 1 comment See all 1 1 comment reply akash.dinkar12 commented Jul 25, 2018 reply Follow Share ∑1 = set of all strings of length 1 ={0,1,2,3} ∑2 = set of all strings of length 2 =∑.∑ ={0,1,2,3}.{0,1,2,3} = 4*4 = 16 strings of length 2 ∑3 = set of all strings of length 3 =∑.∑.∑ = 16 strings of length 2 * {0,1,2,3} = 64 strings of length 3.. srestha can u plz check this?? 0 votes 0 votes Please log in or register to add a comment.
1 votes 1 votes Ans 256 it is a power cube set 24 =16 again another power 16⨉16=256 srestha answered May 20, 2016 srestha comment Share Follow See all 8 Comments See all 8 8 Comments reply Sourabh Kumar commented May 20, 2016 reply Follow Share The power set has 2^4=16 element But wat's the power cube set I don't hear this term before please exlplain 0 votes 0 votes ManojK commented May 20, 2016 reply Follow Share where is power set in the qus ? 0 votes 0 votes srestha commented May 20, 2016 reply Follow Share @Manoj 3 is in power rt? 0 votes 0 votes ManojK commented May 20, 2016 reply Follow Share rt 0 votes 0 votes Sourabh Kumar commented May 20, 2016 reply Follow Share Seshta: can you tell the element in sigma^2 Is the sigma^ 2 is sama as the power set and if possible tell the element in sigma^3 also. Is sigma is treated as a relation .if yes then sigma^3 contains 4^3 elements. and one of the element is (0,0,0) 0 votes 0 votes LeenSharma commented Jul 9, 2016 reply Follow Share Sourabh Kumar ∑2=∑$\times$∑ ∑2={ (0,0) , (1,1) , (2,2) , (3,3) , (0,1) , (0,2) , (0,3) , (2,0) , (1,0) , (1,2) , (1,3) , (2,1) , (2,3) , (3,0) , (3,1) , (3,2) } Number of element in ∑2 =16 ∑3=∑2$\times$∑ and Power set of set ∑ and ∑2 both are different. Let's take a small example A={1,2} Power set P(S)={ $\phi$ , {1} , {2} , {1,2} } and ∑2=∑$\times$∑ = { (1,1) (2,2) , (1,2) , (2,1) } 0 votes 0 votes Sourabh Kumar commented Jul 14, 2016 reply Follow Share @leensharma : according to you sigma^2 contain 16 element and sigma contain 4 element . then sigma^3=sigma^2 * sigma =16*4=64 the answer will be 64. how it comes 256. 0 votes 0 votes mcjoshi commented Oct 10, 2016 reply Follow Share @srestha then, $\Sigma^{5}$ means repeating same process 4 times. If, $|\Sigma| = 2$, then $|\Sigma^2| = 2^2 = 4$, $ |\Sigma^3| = 2^4 = 16$ and then $2^{16}$. 0 votes 0 votes Please log in or register to add a comment.