0 votes 0 votes (A) Context-free languages are closed under union. (B) Context-free languages are closed under concatenation. (C) Context-free languages are closed under intersection. (D) Context-free languages are closed under Kleene closure. im.raj asked May 26, 2016 im.raj 12.3k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 1 votes 1 votes CFL are not closed under Intersection and complement. So option C is False. Ex. L1=anbncm and L2=anbmcm So L1∩L2= anbncn which CSL not CFL. ManojK answered May 26, 2016 • selected May 26, 2016 by rude ManojK comment Share Follow See all 4 Comments See all 4 4 Comments reply rude commented May 26, 2016 reply Follow Share Great example dude, What are you reading for this? 0 votes 0 votes ManojK commented May 26, 2016 reply Follow Share Nothing just practising qus. 1 votes 1 votes rude commented May 26, 2016 reply Follow Share Dude tell me, share your secret :P :D I always get the wrong answer in this. Help me dude. And Do not down vote it. :P 0 votes 0 votes Deepak jain commented Jun 18, 2016 reply Follow Share how did you get C^n here we don't have c^n we just have c^m in both the languages .the intersection should be C^m right ? 0 votes 0 votes Please log in or register to add a comment.