Pipeline SpeedUp

Question

Answer 1

let n number of Instructions.
Number of cycle required for Non Pipeline Architecture = 12 cycle
Number of Clock Cycle required for Pipelined Architecture = (6+n-1)*Stage Delay

Here stage delay is max (all stage delay) = 6 cycle

SPEED UP = (Number of Cycles for Non Pipelined Architecture) / (Number of Cycles for Pipelined Architecture)
                =12n/(5+n)6.               //Assuming n is very large i.e. n is approx same as n+5

SpeedUp = 12n/6n = 2

Comments

How time taken without pipelining $=12$unit.

Why not $3+2+5+4+6+2 = 22$?

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that is after pipelining, before pipelining it is 12 it is clearly mentioned in  the question

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   Lt      (12n/(5+n)*6)  is undetermined form, apply L-Hospital rule  Lt (2)/(0+1) = 2
n->inf                                                                                                           n->inf