26 votes 26 votes In the slow start phase of the TCP congestion algorithm, the size of the congestion window: does not increase increase linearly increases quadratically increases exponentially Computer Networks gatecse-2008 computer-networks congestion-control normal + – Kathleen asked Sep 12, 2014 • edited Jun 20, 2018 by Milicevic3306 Kathleen 10.1k views answer comment Share Follow See 1 comment See all 1 1 comment reply Manu Thakur commented Dec 11, 2017 reply Follow Share In Slow start phase, window size increases by 1 MSS for each received acknowledgement and at the end of RTT, window size increases exponentially. So, (D) is correct option! 16 votes 16 votes Please log in or register to add a comment.
Best answer 32 votes 32 votes Assume that $\text{ssthresh} = 8.$ Increase is exponential in the Slow Start Phase. Answer is option D. amarVashishth answered Nov 6, 2015 • edited May 2, 2021 by gatecse amarVashishth comment Share Follow See 1 comment See all 1 1 comment reply Swati Rauniyar commented Jan 18, 2018 reply Follow Share 1*2 = 2 2*2 = 4 4*2 = 8 , why don't we read it as linear growth? 0 votes 0 votes Please log in or register to add a comment.
11 votes 11 votes ans d)Ref: http://www.ece.virginia.edu/~mv/edu/ee136/Lectures/congestion-control/tcp-congestion-control.pdf Aditi Dan answered Dec 23, 2014 Aditi Dan comment Share Follow See all 0 reply Please log in or register to add a comment.
5 votes 5 votes In slow start cwind size increases exponentially & In Congestion avoidance cwind size increases Linearly. Sandeep Verma answered Aug 23, 2016 Sandeep Verma comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes Option D is correct, Increases exponentially. Sanandan answered Oct 4, 2020 Sanandan comment Share Follow See all 0 reply Please log in or register to add a comment.