1 votes 1 votes Theory of Computation theory-of-computation regular regular-expression finite-automata + – Don't you worry asked Jun 11, 2016 Don't you worry 5.4k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 4 votes 4 votes Start state =q0 and Final state =q2 shekhar chauhan answered Jun 11, 2016 • selected Jun 11, 2016 by Don't you worry shekhar chauhan comment Share Follow See all 3 Comments See all 3 3 Comments reply srikanth43 commented Jun 18, 2016 reply Follow Share it doesn't accept string 11011 0 votes 0 votes shekhar chauhan commented Jun 18, 2016 reply Follow Share it does q0 ==>q1 ==> q3 ==> q1 ==> q3 ==> q2 How about this ? 0 votes 0 votes srikanth43 commented Jun 18, 2016 reply Follow Share done...ok got it. 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes State 0(Input alphabet) 1(Input aphabet) q0 q0 q1 q1 q2 q3 *q2 q4 q0 q3 q1 q2 q4 q3 q4 Now by above state table draw DFA and make q2 as a final state bcz w(x)mod5=2 Paras Nath answered Dec 26, 2016 Paras Nath comment Share Follow See all 0 reply Please log in or register to add a comment.