5 votes 5 votes In the given network of AND and OR gates $f$ can be written as $\text{X}_0\text{X}_1\text{X}_2 \dots \text{X}_n + \text{X}_1\text{X}_2 \dots \text{X}_n + \text{X}_2\text{X}_3 \dots \text{X}_n + \dots + \text{X}_n$ $\text{X}_0\text{X}_1 + \text{X}_2\text{X}_3+ \dots \text{X}_{n-1}\text{X}_n$ $\text{X}_0+\text{X}_1 + \text{X}_2+ \dots +\text{X}_n $ $\text{X}_0\text{X}_1 + \text{X}_3 \dots \text{X}_{n-1}+ \text{X}_2\text{X}_3 + \text{X}_5 \dots \text{X}_{n-1} + \dots +\text{X}_{n-2} \text{X}_{n-1} +\text{X}_n$ Digital Logic isro2008 digital-logic circuit-output + – go_editor asked Jun 11, 2016 edited Dec 7, 2022 by Lakshman Bhaiya go_editor 4.9k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 11 votes 11 votes $(X_0X_1+X_2)X_3+X_4)X_5+\cdots+X_N$ $=(X_0X_1X_3+X_2X_3+X_4)X_5+\cdots+X_N$ $=X_0X_1X_3X_5+X_2X_3X_5+X_4X_5+\cdots+X_N$ $=X_0X_1X_3X_5\cdots X_{N-1}+X_2X_3X_5\cdots X_{N-1}+X_4X_5X_7\cdots X_{N-1}+\cdots + X_N$ srestha answered Jun 11, 2016 edited Nov 25, 2017 by prateekdwv srestha comment Share Follow See all 5 Comments See all 5 5 Comments reply Show 2 previous comments srestha commented Jun 20, 2016 reply Follow Share No option matching 2 votes 2 votes Avantika Dixit commented Jun 28, 2016 reply Follow Share Agree. No option matching ! 0 votes 0 votes dr_Jackal commented Jan 5, 2020 reply Follow Share its option D , there's typo --> "X0X1+X3…Xn−1" should be "X0X1+X2…Xn−1" , but general term says correct. 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes Option A is answer I think sarbesh answered Apr 30, 2017 sarbesh comment Share Follow See 1 comment See all 1 1 comment reply palak bafna commented Jun 6, 2022 reply Follow Share how 0 votes 0 votes Please log in or register to add a comment.