0 votes 0 votes closed as a duplicate of: ISRO2007-01 Digital Logic boolean-algebra + – Isha Gupta asked Jun 12, 2016 • closed Nov 11, 2022 by Hira Thakur Isha Gupta 7.9k views comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes (a+b'+a'b)c' =(a+b'+a')c' =(1+b')c' =c' shivanisrivarshini answered Jun 12, 2016 shivanisrivarshini comment Share Follow See all 4 Comments See all 4 4 Comments reply Pranav Madhani commented Feb 20, 2018 reply Follow Share can u show explaination with kmap? m getting different answer 0 votes 0 votes shivanisrivarshini commented Feb 20, 2018 reply Follow Share Check out this 0 votes 0 votes Saravanakumar M commented Feb 20, 2018 reply Follow Share Is this correct? 1 votes 1 votes shivanisrivarshini commented Feb 20, 2018 reply Follow Share yes its correct 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes =[a+(b'+a')(b'+b)]c' distributive law =[a+(b'+a').1]c' identity =[a+a'+b']c' commutative =(1+b')c' identity =c' by theorem x+1=1 Pravin Paikrao answered Jun 19, 2016 Pravin Paikrao comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes (a+b'+a'b)c' =(a+a'b+b')c' =((a+a')(a+b)+b’)c' =(a+b+b’)c’ =(a+1)c’ =c’ Musa answered Aug 25, 2020 Musa comment Share Follow See all 0 reply Please log in or register to add a comment.