Consider the following code

Question

void main()
{
    int  x=10, y=5;
    swap(x,y);
    print(x,y);
}

void swap(int a, int b)
{
    int c, x=0;
    c=a;
    a=b;
    b=c;
}

what is output using call by text?

a) 5  0

b) 5   10

c) 10   0

d) 10   10

Comments

do error correction please... swap(x,y);;

print(x,y);

Answer 1

according to the concept of inline functions. That is how we represent the concept of call by text or call by name in c ++

The answer should be:

Option A: 5  0

but as per the concept of macros in c i am still not clear on the correct answer for this.

here is a link for anyone who wants to go through the details of this:

http://www.cs.rit.edu/~rpj/courses/plc/lab4/lab47.html#Q12

Comments

But does call by text ensure that modification in called function is reflected in the callee?