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A system is having $8\;\text{M}$ bytes of video memory for bit-mapped graphics with $64$-bit colour. What is the maximum resolution it can support?

  1. $800 \times 600$
  2. $1024 \times 768$
  3. $1280 \times 1024$
  4. $1920 \times 1440$
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Maximum file size = M = 8 MByte = 83,88,608 Byte

A. 800 * 600 *8 byte = 38,40,000 < M 

B. 1024 * 768 *8 byte = 62,91,456 < M      (Ans.maximum resolution it can support)  

C. 1280 * 1024 *8 byte = 1,04,85,760 > M 

D. 1920 *1440 *8 byte  > M 

1 comment

make sense.

But @Arjun sir could you please verify it.
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