4 votes 4 votes The shift operator $E$ is defined as $E [f(x_i)] = f (x_i+h)$ and $E'[f(x_i)]=f (x_i -h)$ then $\triangle$ (forward difference) in terms of $E$ is $E-1$ $E$ $1-E^{-1}$ $1-E$ Numerical Methods isro2009 + – go_editor asked Jun 15, 2016 go_editor 8.1k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 4 votes 4 votes Forward difference operator(delta (D)) D(f(x)) = f(x + h) - f(x) Shift operator , Ef(x) = f(x+h) = f(x+h) - f(x) + f(x) = (1 + D)f(x) so E= 1 + D gives D = E - 1 Kapil answered Jun 15, 2016 selected Mar 13, 2017 by Kapil Kapil comment Share Follow See all 0 reply Please log in or register to add a comment.