The cubic polynomial $y(x)$ which takes the following values: $y(0)=1, y(1)=0, y(2)=1$ and $y(3)=10$ is
Ans D)
y(x)=x^{3}-2x^{2}+1
Now, putting x=0 we get y(x)=0-0+1=1
Similarly x=1 we get y(x)=0
x=2 then y=1
x=3 then y=10