The value of $x$ at which $y$ is minimum for $y=x^2 -3x +1 $ is
Ans B) 3/2
y=x^{2}-3x+1
y'=2x-3
y''=2 // So, y has minimum value
the value at point (2x-3)=0
or, x=3/2
Gatecse
OK @
In d link mentioned below. Yeah. :)