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The value of $x$ at which $y$ is minimum for $y=x^2 -3x +1 $ is

  1. -3/2
  2. 3/2
  3. 0
  4. -5/4
asked in Calculus by Veteran (97k points)
edited by | 1.2k views

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Ans B) 3/2

y=x2-3x+1

y'=2x-3

y''=2 // So, y has minimum value

the value at point (2x-3)=0

or, x=3/2

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