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In a class B subnet, we know the IP address of one host and the mask as given below:

IP address: 125.134.112.66

Mask: 255.255.224.0

What is the first address(Network address)?

  1. 125.134.96.0
  2. 125.134.112.0
  3. 125.134.112.66
  4. 125.134.0.0
in Computer Networks by Veteran (106k points) | 3.2k views

2 Answers

+11 votes
Best answer

Answer A)

ANDing IP address and Network Mask we get Network Address

Mask                 11111111.11111111.11100000.00000000

IP Address         01111101.10000110.01110000.01000010

_______________________________________________________

     NID               01111101.10000110.01100000.00000000

by Veteran (119k points)
selected by
0
how to convert ip address decimal value to binary easy way
0
no easy way other than division
0
ok i got the concept
+4 votes
Porocedure-1:

Network address=IP address  && Network Mask (and operation in binary equivalent).

Procedure-2:

Mask:255.255.224.0  So third octet having 3 bits netid and 5 bits host id

So block size is(2^5) i.e. 0,32,64,96,128......so on

By looking to the ip addres125.134.112.66, third octet 112 comes under 96 subnet. Hence Ans.
by Junior (589 points)
Answer:

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