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2 Answers

Best answer
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11 votes

Answer A)

ANDing IP address and Network Mask we get Network Address

Mask                 11111111.11111111.11100000.00000000

IP Address         01111101.10000110.01110000.01000010

_______________________________________________________

     NID               01111101.10000110.01100000.00000000

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Porocedure-1:

Network address=IP address  && Network Mask (and operation in binary equivalent).

Procedure-2:

Mask:255.255.224.0  So third octet having 3 bits netid and 5 bits host id

So block size is(2^5) i.e. 0,32,64,96,128......so on

By looking to the ip addres125.134.112.66, third octet 112 comes under 96 subnet. Hence Ans.
Answer:

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