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(x'y' + z)' + z + xy + wz
in Digital Logic by (457 points) | 195 views

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Best answer

((x'y')' . z' ) + z + xy + wz

((x+y) . z') + z + xy + wz

xz' + yz' + z +xy + wz

xz' + yz' + xy + z(1+w)

xz' + yz' + xy + z

(x + y)z' + z + xy

(z + z') . (z+ (x+ y)) + xy

z + x + y + xy

x + y + z 

by Veteran (50.9k points)
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0

Can u pls explain this step bit more:

From (x + y)z' + z + xy

To (z + z') . (z+ (x+ y)) + xy

0
what is x + yz = (x + y)(x + z)

so z + z'(x + y) = (z = z')( z + x+ y)
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