simplify Boolean expression to one literals mano 2.4 c ans is :B

Question

A'B(D' + C'D) + B(A + A'CD)

Answer 1

A'B((D'+C')(D'+D))+B((A+A')(A+CD))

=A'B(D'+C')+B(A+CD)

=B[A'D'+A'C'+A+CD]

=B(A'+C'D'+A+CD)

=B(A'+A+C'D'+CD)

=B(1)

Answer 2

A'B(D'+C'D)+B(A+A'CD)

= A'B(D'+C')+B(A+CD)

=A'BD'+A'BC'+AB+BCD
 
=B(A'D'+A'C'+A+CD)

=B(A'D'+(A+A'C')+CD)

=B(A'D'+A+C'+CD)

=B((A+A'D')+(C'+CD))

=B(A+D'+C'+D)

=B(A+C'+D'+D)

=B(A+C'+1)

=B

Comments

WHAT ABOUT THAT REMAINING A

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A+C'+1=A+1=1 =>B.1=B