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ISRO2015-75

• edited by
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9 votes
9 votes

The for loop

for (i=0; i<10; ++i)
printf("%d", i&1);

prints

  1. 0101010101
  2. 0111111111
  3. 0000000000
  4. 1111111111
• edited by
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5 Answers

1 votes
1 votes
i&1 is basically checking whether i is even or odd.If it's even it'll return 1 else 0. Based on this I think output should be A.
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