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4 votes
4 votes
Consider three Process A,B,C to be scheduled as per the SRTF algorithm ,the process A is known to be scheduled first and when A has been running for the 7 units of time ,the process C is arrived and process C ran for 1 unit of time ,then Process B is arrived and completed running in 2 unit of time ,then what could be the minimum burst time of the Process A and C

1 Answer

2 votes
2 votes

Minimum B.T. for A  and C : 12 and 4

How ?

Here As its SRTF, process B is loaded because C has more BT than B. so BT of C has to be 3+1 = 4 ..

and in case of Process A : 5+7 = 12

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