General Aptitude

Question

The surface area of the surface cut from the paraboloid $x^2+y^2+z^2=2$ by the plane $y=0$ is equal to

• A. $2 \pi$
• B. $2 \sqrt{2 \pi}$
• C. $7 \pi / 3$
• D. $13 \pi /3$

Answer 1

x² +  y² + z² = R²

This is an equation of sphere with center at origin.

so R = $\sqrt{2}$

The surface area of the surface cut by y=0 , S = $\Pi$ R²

                                                                          = 2$\Pi$ ..