1 votes 1 votes Solve the Recurrence Relation S(r) - 6 S(r-1) +8 S(r-2) = 3r; S(0) =8, S(1)=7 Combinatory discrete-mathematics combinatory + – LavTheRawkstar asked Jun 26, 2016 retagged Jun 27, 2017 by Arjun LavTheRawkstar 1.8k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes S(r) = c1. 4n + c2.2n + 7.3n Now, put the values of S(0) and S(1) to get c1 and c2 Sushant Gokhale answered Sep 11, 2016 edited Jan 5, 2017 by Sushant Gokhale Sushant Gokhale comment Share Follow See all 9 Comments See all 9 9 Comments reply Show 6 previous comments gauravkc commented Jan 31, 2018 reply Follow Share Can someone give a proper solution to this 0 votes 0 votes rajatmyname commented Feb 28, 2019 reply Follow Share Can you please provide the theory to solve this question? 0 votes 0 votes shashankpant16 commented Nov 26, 2020 reply Follow Share When i solved, i got answer as: S(r) = a.4^n + b.2^n - 3^n+2 Where a = -8 and b = 25, and Particular value will be “-9”. 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes S(r)=((17)(2^r))-(3^(r+2)). where r>=2 and S(0)=8 and S(1)=7 manoj0606 answered Dec 13, 2022 manoj0606 comment Share Follow See all 0 reply Please log in or register to add a comment.