0 votes 0 votes $\int_{-\infty}^{\infty} e^{-x^2}\, dx = \sqrt{\pi}$ Calculus definite-integral + – Kitty35 asked Jun 30, 2016 Kitty35 209 views answer comment Share Follow See 1 comment See all 1 1 comment reply LeenSharma commented Jun 30, 2016 reply Follow Share https://en.wikipedia.org/wiki/Gaussian_integral 0 votes 0 votes Please log in or register to add a comment.