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Assuming that for a given network layer implementation, connection establishment overhead is 100 bytes and disconnection overhead is 28 bytes. What would be the minimum size of a packet in bytes the transport layer needs to keep up, if it wishes to implement a datagram service above the network layer and needs to keep its overhead to a maximum of 12.5% (Ignore transport layer overhead)

A. 512

B. 1024

C 1152

D 768
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this question  tests only aptitude

how ??

since tcp is byte oriented protocol...the overheads are==100+28 =128 bytes

now it asks that

what is the total value for which 12.5 percentage =128

so X*12.5/100=128

X=(128*100)/12.5=1024

option B is the ans

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