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The simplified SOP (Sum of Product) from the Boolean expression

$$(\text{P} + \overline{\text{Q}} + \overline{\text{R}}) . (\text{P} + \text{Q + R) . (P + Q} +\overline{\text{R}})$$ is 

  1. $(\overline{\text{P}}.\text{Q}+\overline{\text{R}})$
  2. $(\text{P + Q}.\overline{\text{R}})$
  3. $(\text{P}.\overline{\text{Q}}+\text{R})$
  4. $\text{(P.Q + R)}$
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6 Answers

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(p+q'+r')=011=3
(P+q'+r)=010=2
(P+q+r')=001=1
So, π=(1,3,2)
Sop form for minterm is (0,4,5,6,7)
Hence the answer is (p+q'r')
Answer:

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