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Given,receiver clock is 0.1% faster than sender clock.

At 1 Mbps bits send by sender = 1000000

receiver clock is 0.1% faster than sender clock so Extra bits received by receiver =  1000000 * $\frac{0.1}{100}$

                                                                                                                      =1000 bits 

Total bits received by received= 1001000 bits

Extra bit per second received by receiver= 1000 bps

Hence,Option(C)1000 bps is the correct choice.

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