1,057 views
0 votes
0 votes

Which of the following functions is NOT injective?

  1. $f(x) = x^3 + 4$ from R to R
  2. $f(x) = x^3 + 4$ from N to N
  3. $f(x) = x^2 + 4$ from R to R
  4. $f(x) = x^2 + 4$ from N to N

2 Answers

0 votes
0 votes
I think C) since it is many to one

That is it is giving same value on positive and negative value of x.

for example, On +2 it is giving 8 and on -2 also it is giving 8. So it is many to one and hence not injective
0 votes
0 votes

c) f(x) = x2 + 4 from R to R is not injective

See injective means one to one function

N here is natural number . Range of Natural number is 0 to +infinity

So, natural number has no chances to be many to one or one to many or many to many relationship.

R is real number. Range of Real number -infinity to +infinity.

So, it has a chance of giving same output in positive and negative numbers

Say, for x= -1,1 f(x) = x^2 + 4 from R to R gets same value.

So, C will be answer

Related questions

3 votes
3 votes
1 answer
1
1 votes
1 votes
2 answers
2
pC asked Jun 19, 2016
749 views
QuestionWhich of the following is NOT True ?Statement 1 : A-( B-C )=(A-B) - (A-C)Statement 2 : A$\bigtriangleup$(B$\cup$C)= (A $\bigtriangleup$B)$\cup$(A$\bigtriangleup$...
0 votes
0 votes
1 answer
3
im.raj asked May 26, 2016
1,636 views
(a) The set of negative integers is countable.(b) The set of integers that are multiples of 7 is countable.(c) The set of even integers is countable.(d) The set of real n...