answer is (C) with assumption...that every appropriate word of document is always present in hash table..
for every word in the dictionary....is placed in one slot of hash table
let boolean var = X
a |
X=T |
aa |
X=F |
ab |
X= F |
... |
|
an |
X= T |
... |
|
ang |
X = F |
... |
|
.... |
|
anger |
X = T |
so the words that are true are available in dictionary..
false surely means the word is not there in dictionary..
increase in the document size doesn't effect the hash table size...as it already has entry for every word arrangement possible...