Ans is b ) 50 percent ?

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Consider a uniprocessor system where new processes arrive at an average of five processes per minute and each process needs an average of $6$ seconds of service time. What will be the CPU utilization ?

- $80$ %
- $50$ %
- $60$ %
- $30$ %

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Given in system there are on an average 5 new processes arrive per minute.

So,Arrival rate = 5 process / min

In every 12 second a ( $\frac{60 }{5}$ )new process arrives in system or we can say every process stays 12 second with the CPU.

Given service time = 6 seconds

CPU Utilization =$\frac{Service \;Time}{Staying\;Time}*100 $

=$\frac{6}{12}*100$=50%

Hence,Option**(B)50%** is the correct choice.

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