0 votes 0 votes Given an image of size $1024 \times 1024$ pixels in which intensity of each pixel is an $8$-bit quality. It requires _______ of storage space if the image is not compressed. One Terabyte One Megabyte $8$ Megabytes $8$ Terabytes Digital Image Processing ugcnetjune2014iii image-compression computer-graphics + – makhdoom ghaya asked Jul 11, 2016 recategorized Sep 30, 2018 by Pooja Khatri makhdoom ghaya 4.9k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
2 votes 2 votes Each pixel needs to store 1 Byte( 8 bit) Total 1024 x 1024 pixels Total storage space = 1024 x 1024 x 1 = 2 10 x 2 10 x 1 = 2 20 = 1 MB Answer B sh!va answered Jul 11, 2016 sh!va comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes Total memory requirements is 1024 * 1024 *8 bits. to convert it to byte we need to divide by 8 then to kb we need to divide by 1024 and then to mega byte again need to divide by 1024, resulting in 1 value. so the result is 1 Megabyte. Prasanjeet Ghosh answered May 18, 2018 Prasanjeet Ghosh comment Share Follow See all 0 reply Please log in or register to add a comment.