Given an image of size $1024 \times 1024$ pixels in which intensity of each pixel is an $8$-bit quality. It requires _______ of storage space if the image is not compressed.
Each pixel needs to store 1 Byte( 8 bit)
Total 1024 x 1024 pixels
Total storage space = 1024 x 1024 x 1 = 2 ^{10} x 2 ^{10} x 1 = 2 ^{20} = 1 MB
Answer B
Total memory requirements is 1024 * 1024 *8 bits. to convert it to byte we need to divide by 8 then to kb we need to divide by 1024 and then to mega byte again need to divide by 1024, resulting in 1 value. so the result is 1 Megabyte.