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2 Answers

3 votes
3 votes
number is  in 2's complement form and sign bit is 1 so it is a negative number and to find original number find its 2'complement

as below

1101010  its one's complement 1010101 add 1 to LSB =1010110 =-22 (note sign bit remain unchanged in complementing)

hence ans is B
edited by
2 votes
2 votes

$2's\ complement \frac{\begin{matrix} &1 &1 &0 & 1&0&1&0\\\end{matrix}}{\begin{matrix}1&0 & 1 &0 &1&1&0 \end{matrix}}$

and  1 0 1 0 1 1 0    =   - 22

       $\uparrow$

negetive sign bit  

Hence,Option(B)-22.

edited by
Answer:

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