1 votes 1 votes Consider a set $A = \left\{1, 2, 3, …….., 1000\right\}$. How many members of A shall be divisible by $3$ or by $5$ or by both $3$ and $5$? 533 599 467 66 Discrete Mathematics ugcnetcse-dec2014-paper2 discrete-mathematics set-theory&algebra + – makhdoom ghaya asked Jul 15, 2016 recategorized Jan 1, 2020 makhdoom ghaya 2.3k views answer comment Share Follow See 1 comment See all 1 1 comment reply asu commented Jul 15, 2016 reply Follow Share 467 0 votes 0 votes Please log in or register to add a comment.
2 votes 2 votes Thanks . For correction :) Number of members divisible by 3 = {3,6,9,........999} //Total 333 terms :easy way =999/3 =333 Number of members divisible by 5={5,10,......995,1000} // Total 200 terms: easy way =1000/5 =200 Number of members divisible by 15= {15, 30, ...990} // total 66 thus total number of members in set = 333+200 -66 =467 sh!va answered Jul 15, 2016 edited Jul 15, 2016 by sh!va sh!va comment Share Follow See all 2 Comments See all 2 2 Comments reply . commented Jul 15, 2016 reply Follow Share isn't number divisible by 15 is included in both divisible by 3 and 5 so we need to subtract 1000/5*3=66.67 333+200-66=467 0 votes 0 votes sh!va commented Jul 15, 2016 reply Follow Share Oops.. my bad... Correcting the answer.. Thanks for pointing it 0 votes 0 votes Please log in or register to add a comment.