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2 Answers

2 votes
2 votes

let we have 2(n) record of 5(M) byte each(since it is asking for first byte we can assume that it is byte oriented or stores byte wise)

record 1 0 1 2 3 4
record 2 5 6 7 8 9

to keep things simple: let we want 1st byte of record 2

which is 5 and we can get by (N-1)M =(2-1)*5=5

so for any N value :: (N-1)M gives the desired logical address.

so C is the ans

0 votes
0 votes
For Sequential access given 1st record is record 1 so

For n=2 and m=5
numbering is->
1 2 3 4 5
6 7 8 9 10

5*(2-1) + 1
m*(n-1)+1
(A) is answer

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