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UGC NET CSE | December 2014 | Part 2 | Question: 07

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The Excess-$3$ decimal code is a self-complementing code because 

  1. The binary sum of a code and its $9's$ complement is equal to $9$. 
  2. It is a weighted code. 
  3. Complement can be generated by inverting each bit pattern.
  4. The binary sum of a code and its $10's$ complement is equal to $9$. 
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Answer : The binary sum of a code and its 9′s complement is equal to 9.
              Complement can be generated by inverting each bit pattern.

Excess-3, also called XS3, is a non-weighted code used to express decimal number's.The Excess-3 code for a given decimal number is determined by adding '3' to each decimal digit in the given number and then replacing each digit of the newly found decimal number by its four bit binary equivalent .The key feature of the Excess-3 code is .that it is self complementing. In other words, the l's complement of an Excess- 3 number is the Excess- 3 code for the 9's complement of the corresponding decimal number.

Reference : Excess - 3

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The key feature of the Excess-3 code is .that it is self complementing. In other words, the l's complement of an Excess- 3 number is the Excess- 3 code for the 9's complement of the corresponding decimal number. For example, the Excess- 3 code for decimal 6 is 1001. The l's complement of 1001 is 0110, which is the Excess-3 code for decimal 3, and 3 is the 9's complement of 6.

Thus, 

  1. The decimal sum (not biinary sum) of a code and its 9′s complement is equal to 9
  2. Complement can be generated by inverting each bit pattern.

Hence, ans: C

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