do while loop

Question

What is the output of the following program?

#include<stdio.h>
void main()
{   int n=3, i=0;
do  {
n=n++;
i++;
}   while(i!=3);
printf(“%d\n”, n);
}

Answer 1

I think it will be 3

In line with post increment n=n++; before assigning updated value to n (ie n+1) n will be assigned with old value (ie 3)

n will be never changed even if the loop runs for infinite times

Comments

n is assigning 3 and then 3++ Are u telling that will causing problem for not increment the value of n? As constant cannot take ++ operator?

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@shiva:   n=n++; will be interpreted as 2 lines 1st n=n//3 will assign to n.

2nd n=n+1;// then it will be incremented.

Then i±± will happen.

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@Sourab kumar:

Sir,

I checked by executing code..

I am getting answer as 3

Value of n is not changing