direct block addressing will point to 12 disk blocks=12*256B
Singly Indirect block addressing will point to 1 disk block which has 256/2 disc block addresses
=128*256B
Doubly indirect block addressing has (256/2)*(256/2) disk block addresses
=128*128*256B
Total File Size=(12+128+128*128)*256B
=4131KB
Or Alternatively you can do direct by formula
Max File size in File System=[#of Direct DBA +(DB Size/DBA)+(DB Size/DBA)^2+(DB Size/DBA)^3+........]*DB Size
Max File Size possible in file System=[ 12+ 256/2+ (256/2)^2]*256B
=4131KB
or 4MB(apx)
No option is true.