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Suppose a file of 10,000 characters is to be sent over a line at 2400 bps. Assume that the data is sent in frames. Each frame consists of 1000 characters and an overhead of 48 bits per frame. Using synchronous transmission, the total overhead time is

  1. 0.05 second
  2. 0.1 second
  3. 0.2 second
  4. 2.0 seconds
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Answer C  Nice question :)

  • No of frames =10000/1000 =10
  • Overhead in one frame =48 bits
  • Overhead in 10 frames =10 x 48= 480 bits.
  • Time needed to send 480 bits= 480/2400 =0.2 seconds.
Answer:

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