2 votes 2 votes A specific editor has $200 K$ of program text, $15 K$ of initial stack, $50 K$ of initialized data, and $70 K$ of bootstrap code. If five editors are started simultaneously, how much physical memory is needed if shared text is used? $1135 K$ $335 K$ $1065 K$ $320 K$ Operating System ugcnetcse-dec2014-paper2 operating-system process + – makhdoom ghaya asked Jul 22, 2016 • recategorized Nov 11, 2017 by Sanjay Sharma makhdoom ghaya 1.7k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
3 votes 3 votes initial stack, initialized data, and bootstrap code can be shared among the editors. Given that text is also shared, then total memory =200+15+50+70 =335K sh!va answered Jul 22, 2016 sh!va comment Share Follow See 1 comment See all 1 1 comment reply rio commented Mar 14, 2018 reply Follow Share how can u elaborate more eg chrome brower same program text will be shared but other would be different @sh!va 0 votes 0 votes Please log in or register to add a comment.
2 votes 2 votes Answer is B, Because text is shared so no need to multiply 200 with 5. and other need each for running so answer is 200+15+50+70=335 A. Dalal answered Jul 11, 2016 A. Dalal comment Share Follow See all 0 reply Please log in or register to add a comment.
1 votes 1 votes Ans (B) 335K <= (200K + 15K + 50K + 70K) Reason is provided in the snapshot below. Ritwik answered Jun 17, 2017 Ritwik comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes 5 editor works simultaneously Each editor must have separate code in each. But they could share initial stack, initialized data and bootstrap code So, total memory required 200*5+15+50+70=1135 K srestha answered Nov 17, 2015 srestha comment Share Follow See 1 comment See all 1 1 comment reply jansbtech commented Jun 24, 2016 reply Follow Share But answer is given as 335K 0 votes 0 votes Please log in or register to add a comment.