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UGC NET CSE | September 2013 | Part 3 | Question: 36

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2^14 =16384  2^13=8192 2^12=4096  so for counting upto 16383 we need 14 bits (11111111111111) so 14 flip flops are required as each flip flop store one bit and these flip flops can be connected in parallel

hence ans is D
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UGC NET CSE | September 2013 | Part 3 | Question: 34
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