4 votes 4 votes Let $R = ABCDE$ is a relational scheme with functional dependency set $F = \left\{A \rightarrow B, B \rightarrow C, AC \rightarrow D\right\}$. The attribute closures of $A$ and $E$ are $ABCD, \phi$ $ABCD, E$ $\Phi, \phi$ $ABC, E$ Databases ugcnetcse-dec2014-paper3 databases database-normalization + – makhdoom ghaya asked Jul 25, 2016 • recategorized Jul 25, 2016 by LeenSharma makhdoom ghaya 2.7k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 12 votes 12 votes {A}+={ A , B , C , D } {E}+={E} Hence,Option(B) ABCD , E. LeenSharma answered Jul 25, 2016 • selected Jul 25, 2016 by srestha LeenSharma comment Share Follow See all 0 reply Please log in or register to add a comment.
2 votes 2 votes Closure(A)=ABCD Closure(E)=E Therefore option B will be right option for it. Paras Nath answered Dec 12, 2016 Paras Nath comment Share Follow See all 0 reply Please log in or register to add a comment.