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4 votes
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Let $R = ABCDE$ is a relational scheme with functional dependency set $F = \left\{A \rightarrow B, B \rightarrow C, AC \rightarrow D\right\}$. The attribute closures of $A$ and $E$ are 

  1. $ABCD, \phi$
  2. $ABCD, E$ 
  3. $\Phi, \phi$ 
  4. $ABC, E$ 
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2 Answers

Best answer
12 votes
12 votes

{A}+={ A , B , C , D }

{E}+={E}

Hence,Option(B) ABCD , E.

selected by
2 votes
2 votes

Closure(A)=ABCD

Closure(E)=E

Therefore option B will be right option for it.

Answer:

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